(v^2-v-12)/(32-2v^2)

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Solution for (v^2-v-12)/(32-2v^2) equation: 


D( v )

32-(2*v^2) = 0

32-(2*v^2) = 0

32-(2*v^2) = 0

32-2*v^2 = 0

-2*v^2 = -32 // : -2

v^2 = 16

v^2 = 16 // ^ 1/2

abs(v) = 4

v = 4 or v = -4

v in (-oo:-4) U (-4:4) U (4:+oo)

(v^2-v-12)/(32-(2*v^2)) = 0

(v^2-v-12)/(32-2*v^2) = 0

v^2-v-12 = 0

v^2-v-12 = 0

DELTA = (-1)^2-(-12*1*4)

DELTA = 49

DELTA > 0

v = (49^(1/2)+1)/(1*2) or v = (1-49^(1/2))/(1*2)

v = 4 or v = -3

(v+3)*(v-4) = 0

((v+3)*(v-4))/(32-2*v^2) = 0

( v+3 )

v+3 = 0 // - 3

v = -3

( v-4 )

v-4 = 0 // + 4

v = 4

v in { 4} 

v = -3

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